Saturday, 28 September 2013

Keeping model after form submission

Keeping model after form submission

I have the following model used for a quiz, I am trying to submit a form
and pass the existing model back to the Action as it has already been
initialized in the Index action.
public class QuizModel
{
private List<string> _Responses;
public List<string> Responses
{
get
{
if (_Responses == null)
{
_Responses = new List<string>() { "Response A", "Response
B", "Response C", "Response D" };
}
return _Responses;
}
}
public int? SelectedIndex { get; set; }
public string Question { get; set; }
}
With the following View:
<div class="title">Question</div>
<span id="question">@Model.Question</span>
@if (!Model.UserHasAnswered)
{
using (Html.BeginForm("Submit", "Quiz", FormMethod.Post))
{
for (int i = 0; i < Model.Responses.Count; i++)
{
<div class="reponse">@Html.RadioButtonFor(m => m.SelectedIndex,
i)@Model.Responses[i]</div>
}
<input type="submit" value="This is the value" />
}
}
else
{
<div id="explanation">@Model.Explanation</div>
}
And Controller...
//
// GET: /Quiz/
public ActionResult Index()
{
QuizModel model = new QuizModel()
{
Question = "This is the question",
Explanation = "This is the explanation",
UserHasAnswered = false
};
return PartialView(model);
}
//
// POST: /Quiz/Submit
[HttpPost]
public ActionResult Submit(QuizModel model)
{
if (ModelState.IsValid)
{
int? selected = model.SelectedIndex;
model.UserHasAnswered = true;
}
return View("Index", model);
}
When the model comes to the Submit action it only contains the
SelectedIndex and not Question or Explanation properties. How can I tell
my view to pass the original model it received back to the Submit action?

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